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CURVE TABLES. <br /> Published by KEUFFEL & ESSER CO. <br /> HOW TO USE CURVE .TABLES. <br /> ;1 7 <br /> '1 ' g Table I. contains Tangents and Externals to a 1°curve. Tan.and <br /> t.to any other radius may be found nearly enough,bydividing theTan. <br /> r Ext.opposite the given Central Angle by the given degree of curve. <br /> 3 3 n a To find Deg. of Curve, having the Central Angle and Tangent: <br /> Divide Tan.opposite the given Central Angle by the given Tangent. <br /> 1 © j 3� yB � To find Deg. of Curve, having the Central Angle and External: <br /> Divide Ext.opposite the given Central Angle by the given External. <br /> y G a To find Nat.Tan.and Nat.Ex.Sec.for any angle by Table I.:Tan. <br /> 8 o d or Ext.of twice the given angle divided by the radius of a 10 curve will <br /> be the Nat.Tan.or Nat.Ex.Sec. <br /> EXAMPLE. <br /> Wanted a Curve with an Ext.of about 12 ft. Angle <br /> of Intersection or 1. P.=23° 20' to the R. at Station <br /> 542+72. S 7 3 h� <br /> Ext.in Tab. I opposite 23°20'=120.87 3,9 30 <br /> - 120.87=12=10.07. Say a 10°Curve. <br /> Tan.in Tab. I opp.23°20'=1183.1 <br /> 1183.1=10=118.31. <br /> Correction for A.23°20'for a 10°Cur.=0.16 <br /> 118.31-1-0.16=118.47=corrected Tangent. <br /> - (If corrected-Ext.is required find in same way) <br /> - <br /> Ang.23'20'=23.33 =10=2.3333=L.C. <br /> --r 7 "� L 2019j'=def.for sta. 542 I. P.=sta. 542+72 <br /> / 3 39' 3 0' 40 4911= u " it cc <br /> +50 Tan.= 1 .18.47 <br /> 7 19I y <br /> k W +� Q �� I 6 i 904911= " " " 5 B.C.=sta. 541 53. L 6 <br /> 11°40'= " " " 543 L.C.= 2 .33. S �C <br /> -F �_-._--• <br /> /L 86.86 E.C.=Sta. 543x-86.86 ; � 1 1.7 <br /> Jt 0 as /J / ' l7 <br /> 100-53.53=46.47X3'(def.for 1 ft.of 10°Cur.)=139.41'= <br /> 2°19;'_def.for sta.542. l 6 ft.i L <br /> 0 <br /> 6 <br /> Def.for 50 ft.=2o 30 for a 10 Curve. 7 <br /> 3'9 3 Def.for 36.86 ft.=1°501'for a 10'Curve. <br /> pe' IAAng. 3°20. <br /> 10•Curve <br /> 2 <br /> I <br /> p 4 <br />