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I <br /> CURVE TABLES. <br /> Published by KEUFFEL & ES SER CO. <br /> h HOW TO USE CURVE TABLES. <br /> _ �p f Tablej. contains Tangents and Externals to a 1°curve. Tan.and <br /> t.to any other radius maybe found nearly enough,bydividing the Tan. <br /> r Ext,opposite the given Central Angle by thegiven degree of curve. <br /> iv To Tan.find Deg. of Curve, having the Ceentral Angle and Tangent: <br /> To find Deg of Curosite the ve, haviven ing thntral e Angle <br /> ralthe <br /> Angle and ETangent. <br /> ternal: <br /> ivide Ext.opposite the given Central Angle by the given External. <br /> To find Nat.Tan-and Nat.Ex.Sec.for any angle by Table I.:Tan. <br /> Ext.of twice the given angle divided by the radius of a 1°curve will <br /> _ the Nat.Tan.or Nat.Ex.Sec. <br /> EXAMPLE. <br /> Wanted a Curve with an Ext. of about 12 ft. Angle <br /> of Intersection or 1. P.=23° 20' to the R. at Station <br /> - 3 v l -- 542+72. <br /> Ext.in Tab. I opposite 230 20'=120.87 <br /> 120.87=12=10.07. Say a 10°Curve. <br /> Tan.in Tab. I opp.231 20'=1183.1 <br /> 1183.1=10=118.31. <br /> --- - - Correction for A.230 20'for a 10°Cur.=0.16 <br /> 118.31-}-0.16=118.47=corrected Tangent. <br /> Z '-J- (If corrected Ext.is required find in same way) <br /> Ang.23°20'=23.33 =10=2.3333=L. C. <br /> rf d - — 2°19j'=def.for sta. 542 1. P.=sta. 542+72 <br /> 4°49,x'_ " +50 Tan.= 1 .18.47 <br /> •O _ — 70191i= u a a 543 li <br /> 1 G G C <br /> go49J,r ,� u a +50 B. .=ste_ 541- 53.53 <br /> _ G 110 40'_ « u 543+ L. C.= 2 .33.33 <br /> 86.86 E.C.=Sta. 543+86.86 <br /> 7 ? ,lj 100=53.53=46.47X3'(def.for 1 ft.of 10°Cur.)=139.41'= <br /> / b - 2°19;'=def.for sta.542. <br /> Def.for 50 ft.=20 30'for a 10°Curve. <br /> - Def.for 36.86 ft.=10 50 'for a 10°Curve. <br /> Z 4 o J' <br /> >A <br /> LP.A"9.23.-101 <br /> I <br /> I II <br /> 10•Curve <br />