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.9,;r <br /> sr✓-4 >. <br /> 7 2 z yG TRIGONOMETRIC FORMULIE i��,�y 00 <br /> ifl3J' <br /> 2-, B <br /> 3 z3 4-d7 5 1 <br /> a7' !r ac y� ao a 'G>sj_ a <br /> a <br /> aA A C <br /> ' C C b <br /> Right Triangle Oblique Triangles <br /> 3 L 9 t y .r ✓ P 3 P 4 a__6_S Solution of Right Triangles 3 6 g <br /> For Angle A. sin =a cos= b tan= a cot= b sec =6 cosec= o e f <br /> 3f 39. � A �. 3 Z c , c , b , a, b, <br /> j t s, ?,9 v----- (liven Requireda 2 a <br /> 3. G L a, b A, B,c tanA=b = cot B,c = a2+ 2 = a 1 + as <br /> A, B, b sin A= = ll <br /> cos B,b a: <br /> A,a B, b, c B=90°—A b =a cotA,c= a a <br /> ? 4',f 4 sin A. <br /> 1 <br /> 7 1 A+b B,a, a B=90°—A,a = b tan A c= b /+ 41 y,r" <br /> s A. <br /> A,a B, a, b B=900—A,a=c sin A,b=c cos A, <br /> %a i ; <br /> a 0 a 7, / Solution of Oblique Triangles <br /> tltaea Required <br /> 'A, B,a b, a, C b=asin B C= 180'—(A+ B) a — asinC <br /> 3 Z _ rain A ' <br /> �? �_ - �' �. '/ sin A <br /> A, a, b B, c, C sin B= b sin A C,= 1800—A B a sin C <br /> r a = <br /> a ( f ), sinA <br /> i <br /> " �' .$ k a, b, C A, B, c A+B=180°—C,tan'(A—B)— a—b)tan a(A+B) <br /> y v 3 y L ) a sin C <br /> a sin A �-! <br /> .4 b._c. A, B, C s=a+b+a,sin'A= <br /> 2 b e 2 3 3 z' <br /> . <br /> 3 <br /> sin'B=V 180b—(A+B <br /> c Area S=a+b c, area a7(7—a <br /> �. ✓s G q" A, b, c Area area = b c sin A <br /> 3_ S' 7 5 g -G L = A,B,C,a Area area =a2 sin'B sin C 7 s <br /> �S. o 3 , <br /> REDUCTION TO HORIZONTAL <br /> Horizontal <br /> distance=Slope distance multiplied by the <br /> o cosine of the vertical angle.Thus:slope distance=319.4 ft. <br /> j S / —_..6! •4 S} // S" it (� a1star a Vert. angle=50 10+. From Table,Page IX.cos 56 lot-- <br /> Y <br /> o'=. <br /> 3� ^(� ( 7 S�oPe 1e 9959. Horizontal distance=319.4?C 9959=$18.09 ft. <br /> `F _„__,• 3 `f ,,,.�, •,�' a .prg a Horizontal distance also=Slope distance minus slope <br /> Y Ll rt 9 3 �e distance times (1—cosine of vertical angle). With the <br /> same figures gores as in the preceding example,the follow- <br /> 0.11Horizontal distance log result is obtained.Cosine 50 10'=.9959.1—.9959=.0041. <br /> 310,4X pp4l=l.31.319.4-1.31=318.09 ft. <br /> ' 3 " f When the rise a known,the horizontal distance is approximately:—the slope dist- <br /> _ 7 ance less the square of the rise divided b7 twice the slope distance. Thus:rise=14 ft., <br /> J` p o slope distance=302.6 ft. Horizontal distane@=L3M6—14 X 14=302.6-032=80228 ft. <br /> 2 X3026 <br /> ( ��•� MADE IN U.B.A. <br />