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FIE BO K 52-W CURVE-- CURVE TABLES. <br /> Published by KEUFFEL & ESSER CO. <br /> HOW TO USE CURVE TABLES. <br /> Table I. contains Tangents and Externals to a P curve. Tan.and <br /> Ext.to any other radius may be found nearly enough,bydividing the Tan. <br /> or Ext.opposite the given Central An le by the given degree of curve. <br /> ------- To find Deg. of Curve having the Central Angle and Tangent: <br /> - Divide Tan.opposite the given Central Angle by the given Tangent. <br /> 7 •" Z 3 � To find Deg. of Curve, having the Central Angle and External: <br /> - - - --- Divide Ext.opposite the given Central Angle by the given External. <br /> To find Nat.Tan.and Nat.Ex.See.for any angle by Table I.:Tan. <br /> - - --- _ or Ext,of twice the given angle divided by the radius of a V curve willbe the Nat.Tan,or Nat.Ex.Sec. <br /> - EXAMPLE. <br /> - _ Wanted a Curve with an Ext.of about 12 ft. Angle <br /> of Intersection or I. P.=23° 20' to the R. at Station <br /> 542+72. <br /> V ` Ext.in Tab. I opposite 23°20'=120.87 <br /> - 120.87+12=10.07. Say a 10'Curve. <br /> - - <br /> Tan.in Tab. I opp.23°20'=1183.1 l <br /> -`� - 1183.1=10=118.31. ': <br /> D f r - <br /> _ _ Correction for A.23°20'for a 10°Cur.=0.16 <br /> - - - <br /> 118.31+0.16=118.47=corrected Tangent. <br /> (If corrected Ext.is required find in same way) <br /> Ang.23°20'=23.33 +10=2.3333=L.C. <br /> 2°19Y=def.for sta. 542 L P.=sta. 542 -72 <br /> --- - <br /> `- �.� .r - - - - T 192'- 550 Tan.. = 1 .18.47 <br /> - -- _ 43 <br /> 9°4921= u a +50 B.C.=sta. 541+53.53 <br /> ----- 11°40'= + L.C.= 2 .33.33 <br /> _ 86.86 E. C.-Sta. 543-x-86.86 <br /> -- - 100-53.53=46.47X3'(def.for 1 ft.of 10°Cur.)=139.41'= <br /> 2° 192'=def.for sta.542. <br /> -- Def.for 50 ft.=2°30'for a 10°Curve. <br /> Def.for 36.86 ft-1°502'for a 10°Curve. <br /> _ s* <br /> Px <br /> - - - 10•Curve <br /> r <br /> w <br /> F <br /> dP <br /> - - <br /> 01 <br /> - dp <br /> ... �� <br />