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TXIGONOMETRID,FORMULA, // � <br /> 3, 57+ �.� B B <br /> a <br /> 7 a <br /> .Z lei ZJr p C A C <br /> 3�� ) t , - Oblique Triangl <br /> e ,�„�,,,w.,�.,--- � es <br /> / $' <br /> 2 q 2 � ,. 7L Solution of 16t Tet an <br /> • �f //� c'Z—. 3 F <br /> � a b a <br /> J 1 or — Cos—— a" = a c= <br /> a .a tan= 7, ,se b, cosec= a <br /> cot <br /> s .✓'' ¢� - (liven a <br /> / 'T a, b tan A—b= cot B,o = a a <br /> 2 •3 ° �' 3 3 <br /> sin coeBb— <br /> �}. e a i <br /> rd,as B=90°—A,b , <br /> -7 Baso° <br /> _ _ Q <br /> S <br /> -A <br /> B 90° 'A =osin A,b= 3 <br /> lotion of Oblique 'j'nan les <br /> .� S_ '�lren a sin B - S <br /> z-'-1- ,*• s b= sin A ' C 180°—.(A+B), a=,a sin C <br /> sin A <br /> / �+ a, b" t7 sin g= bsaArC,= 1'� fA+B c _ aeinC <br /> x ' sin A <br /> / \ a. f E 0. b, 4 -180°—C,tan � —b)tan (A_BJ <br /> 7 , 1 Z asB)Claa+b , <br /> 1 <br /> sinA <br /> �/tom <br /> b a C s=a b a-- a—c N4c-e <br /> ! ,D"1 - . ,, a c ,C=180°—{A+B) <br /> a a+b+ ol <br /> b <br /> e= 2 ,_area, <br /> 1 , <br /> 1 2 A, b, c e area = b a sin A k <br /> / <br /> as sin B sin C �� 1 <br /> A,B,C,a area = y. <br /> 2sinA <br /> o � k <br /> DUCTION TO HORIZONTAL_�4"- "- <br /> Horizontal distance=Sloe lied by the <br /> cosine of the vertical angle. slopediataace=319.41t. <br /> t7 9 i Vert. angle=60 ICY. Prom T� 1%Page I•cos 5-101= <br /> ope 9869. Horizontal distance=g�jw4X.9669=91&09 fL <br /> diostia�bmeeg distance— ine of va al an¢lnd <br /> e Witt the <br /> . J _ same figpr a as in the pre eaampla,the follow- <br /> _ Horizontakfi ing result is obtained. lsa le <br /> =•8969,1—.9969=.00{L <br /> ��4 % / y ' ---- When the riesis sown.th&e n r metal a1.31iraiee 1 p 31&08 ft. <br /> ante less the iqa of the rise di�Ided by twice the slope dis atelce. h 8 eoloDe dist- <br /> slope distawx+-a01t ft. Horizontatdbtaaoe.-a08. 14 X 14 OW 14 ft.; <br /> i <br /> 1 <br /> , <br /> S . <br /> - - .. <br />