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— B <br /> 9Z <br /> ' �} b A <br /> , a p <br /> �Right e -Oblique TriasRles <br /> _ Solution of Right Tfiaaghu <br /> 34 0 L 1 5 Z 5 Far Angie sin a,eon=Q,t�= 3�,cot=a,we=b,COaeC� <br /> y 5`Z l'u (livenired, 3 <br /> "? a,b B,a ' ton d=b=cot B,e= a ! =a 1 ; <br /> 3Gy 161 a= <br /> a 'B, b sin A®a=Cos B,b-%/ o+a a--a <br /> A,a B;'b, o B=90°—A,b=a cotA,a= a <br /> sin A. <br /> -Ar b B,a, a B e 90°A,a= b tan A,a=ow A. <br /> B, a, b I B=W—A,a=asinA,b=.aamsA, <br /> 4 / 2 ` 3 Solution of Obliqqp <br /> G <br /> Given_ onl ed <br /> 0 b= a sr B C m I80*-..4A A�" a—a sis <br /> y sin A ' sin A <br /> d sin C <br /> a sin B=b uan A,a= 1800—(A+.B),e= A "3 <br /> / :a A+B-180°—C,tan j(A—B)=L n— B), <br /> a sin a <br /> ein A <br /> � ja-}-b�-6 8.-• i—a <br /> 2 ,sin�A= <br /> sin+JB= s a'�° ,U!:�180°-(A+B) <br /> a, b, a a=a2,area = s a—a 3 a•--7f'� . <br /> 2- baeinA F'' <br /> . . <br /> "' , b, a area __-_..._ <br /> s i 71/ A'Bt C, = <br /> a area y at sin B sin 0 <br /> 2 sin A }: <br /> ' REDUCTION TO HORIZONTAL <br /> �,� " . �Horlzomw distance- the <br /> �M�S.tlPtt. a ',�"^♦; <br /> �1Opa 4 <br /> �� tlsagl;(1 Ot�1e ~ <br /> Horizontal ° was In a � na as�ayls,th®ton'.- <br /> i _ 4-1�1 6Q10F 1�6Y 1—AM=.00{1. <br /> :. When the #lA i� �}�y; �the slope dist- <br /> less <br /> Vase the Wuals rfse tilr Thus:rise=14 ft. <br /> I supe distaaCe�lAq alt. Sorizon,al 8—= 8=i0R 8-0.n2—sA0 96 ft. <br /> 'Al TIMM <br /> F <br /> f <br />