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RCURV� i �6 <br /> j A.ND, fA&E5:.,. <br /> "wish"M ftgane D1stsgaa,06. <br /> �L. 4P• <br /> 't.,-f' <br /> i t <br /> I <br /> CURVE50 <br /> >E08ltl <br /> j1. Radius R= <br /> I sin D/2 <br /> 2. Degree of Curve: D=1'00 L• Also,sin D/2 50 <br /> = <br /> a <br /> 3. Tangent T=R tan I. Alec,T=Tfor_l <br /> Length of Curve: L=100 D <br /> i 5. Long Chord L. C.=2ksin 3 . <br /> Middle Ordinate: M-R (I-�oos 11 s <br /> 7. External E— R <br /> R. Also, E=T tan Y r <br /> cos I <br /> EXPLANATION AND USE OF TrsTAs ; <br /> i Given P.I.Ota.83+#0.7.1-45*2W and D-6.30'find: <br /> fltatioas—P,C.-P.L—.T. T-T for Curve+ C. From Tolm V and VI <br /> T—2398'8+.197—308.32—3{68 82. Ota P. C. 83{-40.7—(8+6$,p)..!7p+n,,$..., <br /> P.T.-P:C.+L,and L-1d0��1bU ��73a lheesfore,P.'[.�(7ff=f 788B){ <br /> j +(8-}•99:38)�Sdt69.78: } <br /> no <br /> i ( iimately) <br /> i ', aw*OeIIoMf tthie-dTuataes6oeen.tPcreAm�dMfiah�leII �oR.et for 1001 —5 <br /> .6 f[seeett DA,sst <br /> s lee <br /> i -80—fats.P.C..87.82.Hgoea efitee0.ta 66 X(27.12)* <br /> —.432 ft.Alj4,WvotO of apy P <br /> j dbtanoe divided by Woe ttir raiiue emtiM(a rro:iesate )the digt t�eq froth <br /> � to curve.Thus(87`.6 +(tX88I.9M'i.43! <br /> Ddleetions--Deflection•an1e-jj D for 100 ft.,X D for 50 ft.,etc.For"X"ft.. <br /> Deflection Angle(in minutes)—.$XX XD.For Ota.80 of above curve Deflection Angie <br /> �.3 X27.62 X6.5 53.86'.Also Deflection <br /> Angle—dfl.for I ft.from Table I);I XX-1:95 <br /> f X 27.62—M.W. For Ota.Ian'Deflection Angle�5 .88�+6� —4.8.88'. <br /> XXttsUs—fihom Table V for 1•our",with central an0e of 45F 20',jk�4*.6. <br /> Therefore,for 6'Wourve,E4.-6*Cereeati n h.Table VI-'7.37#+AN-7.417. <br /> i <br /> WON m <br /> i <br /> I <br /> t r <br />