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y <br /> f CURVE_ AND RE TABLES <br /> y ea, pUCT'I_ Itabli.>zd b7=upa•Diqtgren Oo. <br /> I <br /> 4, � . Ars: . t.y s <br /> CURVE FORMULAS <br /> -__ - -- 50 <br /> 1. Radius R­ <br /> sin n D/2 <br /> - - 2. Degree of Curve: D=1'00 L Also,sin D/2=R, <br /> I <br /> _ -- <br /> - 3. Tangent T=R tan%L. Also,T= D Tfor P curve+C. <br /> 4. Length of Curve: L=100 D <br /> _ 5. Long Chord L.C.=2R sin I. <br /> 6. Middle Ordinate: M=R(1-coo I) <br /> - . 7. External E= R. Also, E=T tan Y4 I. <br /> -_ - cos �I- <br /> - <br /> -_- ZIPLANATION AND USE OF TARL28 <br /> _- Given P.I.fits.83+40.7,1-45*20'and D-6-301 find: <br /> --� <br /> - - stations—RC.-P.I.-T. T-T for 1•Curve <br /> -�---t,G.. From Tables Y and VI <br /> I <br /> -- - - <br /> T-2398'8+.197 6.5 -368.32 r32. <br /> 8+688ta P. C.-83+40.7-(3+68,32)-79+72.38. <br /> -- <br /> P.T. C.+L,and LJ1fl0 -l3-697.38 Therefore,P.T.-(79-1-72.38) <br /> � 00?'8:b#"3 <br /> .8 , <br /> +(6+97.38)-86+69.7& <br /> 11 <br /> Oft�efa--Ta <br /> _ ngeat ofLeft • zimatel7) 41rwd witb D and. with the <br /> square of the distance.Fr6in Tea-11 nt Offset far X00;ibey-5.669 feet.Distance <br /> - 27 <br /> -80-Sts.P.C.-27.82.Henceaesel- 6aXC- 2)A�.433 ft.Alip,square of my <br /> distance,divided by twice Ohs raiMps (sppro"'Y#_a*sj7)the distance from tangent <br /> - _- - to curve.Thus(27.62)s+(2X881: . 2 t. <br /> Deflections—Deflection raungle->y D for loo ft.,X D for 50 ft.,etc.For"X"ft., <br /> _--.--._-_----- -------- Deflection Angle(in minutes)-.8 XX XD.For Sta.80 of above curve Defieetion An le <br /> -.3 X27.62 X8.5-53.861.Also Deflection An - 8 <br /> Angle dfl.for I ft.f Tagle III XX-1.95 <br /> - ---_ ----- X 27.62-53.881. For lits.181 Deflection Angle=53.86'+66 '-4°8.86'. <br /> - -- <br /> >hternsls—From Table'V'for I•our",with central anile of 45.20',E-479.6. <br /> - ---- - <br /> _ Therefore,for 6.Wourve,E� � Correction from Table VI-7.378+.039-7.417. <br /> f <br /> • <br />