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7 \ <br /> Its <br /> Tmow;N <br /> CURVE AND REDUCTION TABLES <br /> Published by lvssae Dlstalsn Co. <br /> r ' <br /> I <br /> fPoKs.a[_ i <br /> C re,P C.g"C <br /> OVIVE FORMVLAB <br /> 50 <br /> 1. Radius R=sin/2/2 <br /> I rrrr = I .n _b0 <br /> s r Y 2. Degree of Curve: D 100 L Also,sl D/ 2 R <br /> Nyo A n,7' Tfor 1°curve <br /> 3. Tangent T=R tan I. Also,T= D +C. <br /> A_✓f, 4. Length of Curve: L=100 D <br /> 5. Long Chord L.C.=2R sin I. <br /> 6. Middle Ordinate: M=R (1—cos I) <br /> h' 7. External E= R R. Also E=T tan I. <br /> _ Cos I ' <br /> •���`�' <br /> A 4 EXPLANATION AND VSE OF TABLES <br /> v�s� <br /> ()/ Given P.I.Sts.83+40.7,1-45'20'and D-6°30'find: 1 <br /> tStattoas—P.C. P.I.-T. T-T for P CurveD { C. From Tables,V and VI <br /> T- 6.5 +.197 <br /> 2392.8368.32-a+68 32. fits P. C.-83+40.7-(8+68.32)-79+72.38. <br /> P.T.-P.C.+L,and L-100 W-140465"33-09738. Therefore.P.T.-(79+72.38) <br /> +(6+97.38)-86+69.78. <br /> Offsets—Taugeat a8lseta �►ar� ( zimately) dtreoty with D and with the <br /> /�A �S� ©`, square of the distance.Ftan'Ta art III nt Offset foF 100 test-5.669 feet.Distance <br /> -80-Sts.P.C.-27.62.Renee offset-&66 X(27.62)1-.482 ft.Akio,square of any <br /> 100 : <br /> distance,divided by twice the rafts egnski{approximately)the distame from tangent <br /> "$ to curve.Thus(27.62)1+(2XM.95)-.412 rt. <br /> Deflections—Deflections- Door 100 tt., D for 80 ft.,etc.For"X"ft. <br /> - <br /> a <br /> Angle(in minutes)-.$XX XD.For Sts.80 of'above curve Deflection An�1e <br /> l� -.3 X27.62 X6.5-53.86'.Also Deflection Angle-dfl.for L ft.from Table III XX-1. 5 <br /> - X 27.62-53.86'. For Sta.191 Dbfleetioa Angle*-53:88'+6�2 -4'8.86. <br /> !sternals—From Table V for P CUM,with Central angle of 46'W.E-479.6. <br /> Therefore,for 8"30r curve,E79 <br /> -4 6+Cdrreotion from Table t'I-7.x78+.08 -7.417. <br /> m <br />