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inches <br /> Ti = 466 Ib/in <br /> T2s = 660 Ib/in <br /> T2 = 762 Ib/in <br /> Per API 620, the magnitude of the total circumferential force acting on any vertical cross section <br /> through the compression ring region shall be computed as follows: <br /> Q =T2wh +T2swc-Ti RrSin(a) Note that if Q is negative, compression is indicated. <br /> Q = 2,205 + 1,762 - 19,564 <br /> Q = -15,597 <br /> Ac, the required compression ring reinforcing area= Q/15,000 <br /> Ac= 1.039775 sq. inches <br /> Aa > Ac <br /> 1.32523 > 1.039775 TRUE <br /> and since Q is negative the following condition must be true also. <br /> whSin(a) > 0.015 * Rc <br /> 1.447375 > 1.26 TRUE <br /> Since both conditions are true, knuckle region is adequately reinforced. <br /> 5) Check Measured Shell Thickness vs Required Shell Thickness <br /> The required shell thickness is to=T2s/SE2 <br /> 0.062007 However, thickness must beat least 0.100" per <br /> API 653, so final required shell thickness is 0.100 <br /> tc > to <br /> 0.236 > 0.100 TRUE <br /> 6) Check Measured Cone Bottom Thickness vs Required Cone Bottom Thickness <br /> The required cone thickness, thr, is the greater of the following 2 formulas <br /> thr=Ti/SE1 or thr=T2/SE1 <br /> thr= 0.043782 thr= 0.071598 <br /> thr= 0.071598 However, thickness must be at least 0.100" per API 653, so final required <br /> cone bottom thickness is: thr= 0.100 <br /> th > thr <br /> 0.240 0.100 TRUE <br />