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Mass-Volume Calculation of Dissolved Hydrocarbon-Impact <br /> FLAG CITY CHEVRON - 6421 Capital Avenue, Lodi, CA <br />' Assumptions <br />' • A total volume of 1,036,795 gallons was extracted from wells EW-2, EW-4, EW-5,EW-6, <br /> EW-7,EW-8,EW-9 and EW-10 between 09 November 2000 and 31 December 2000 (based <br /> on manifest records between 09 and 20 November 2000 and based on effluent flow meter <br />' observations between 22 November and 31 December 2000) <br /> • Data collected from the pump and treat influent and extraction well-head grab ground water <br />' samples were representative of general extracted ground water conditions <br />' One cubic foot of water contains 7 48 gallons, conversely, one gallon of water is equivalent to <br /> 0 1337 cubic feet, so the volume of processed water is given by <br />' V= (1,036,795 gallons)(0 1337 &/gal) = 138,620 ft' processed water <br /> One gallon of water weighs 8 337 lbs /gal at 60°F, so the mass of processed water is given by <br />' MWa,� = (1,036,795 gallons)(8 337 lbs/gal) =8,643,760 lbs. processed water <br />' Multiplying the mass of the processed water by the average MTBE concentration (494 µg/l)yields <br /> the approximate mass of MTBE removed from processed coater <br /> MMTsr= (8,643,760 lbs)(0 000000494) =4.27 lbs MTBE <br /> A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to kilograms of <br /> MTBE <br /> MMTB.E= 4 27 lbs MTBE (0 4536 kg/lb) = 1,937 g of MTBE <br /> Advanced GcoEnvironmental,Inc <br />