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Mass -Volume Calculation of Dissolved MTBE -16 April 2002 to 22 May 2002 <br />0 FLAG CITY CHEVRON - 6421 Capitol Avenue, Lodi, CA <br />Assumptions <br />• A total volume of 287,717 gallons was extracted from wells EW -4, EW -5, EW -9 and EW -10 <br />between 16 April and 22 May 2002 (based on effluent flow meter observations) <br />• Data collected from the pump and treat influent water samples were representative of general <br />extracted ground water conditions <br />One cubic foot of water contains 7 48 gallons, conversely, one gallon of water is equivalent to <br />0 1337 cubic feet, so the volume of processed water is given by <br />V= (287,717 gallons)(0 1337 ft /gal) = 38,468 ft' processed water <br />One gallon of water weighs 8 337 lbs /gal at 60"F, so the mass of processed water is given by <br />Mwatu = (287,717 gallons)(8 337 lbs /gal) = 2,398,697 lbs. processed water <br />Multiplying the mass of the processed water by the average MTBE concentration (04-16-02= 33,ug/L <br />and 05-22-02 = 28 ,ug/L, avg = 30 5 ,ug/L) yields the approximate mass of MTBE removed from <br />processed water <br />MSE = (2,398,697 lbs)(0 0000000305) = 0.07 lbs MTBE <br />A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to grams of MTBE <br />MMTHE = 0 07 lbs MTBE (0 4536 kg/lb) = 32 g of MTBE <br />Advanced GeoEavzronmental, Inc. <br />