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' Mass-Volume Calculation of Dissolved MTBE - 06 December 2000 to 03 January 2001 <br /> FLAG CITY CHEVRON- 6421 Capitol Avenue, Lodz, CA <br />' Assumptions <br />' • A total volume of 684,501 gallons was extracted from wells EW-2, EW-4, EW-5, EW-6, <br /> EW-7, EW-8, EW-9 and EW-10 between 06 December 2000 and 03 January 2001 (based <br /> on effluent flow meter observations between 06 December and 03 January 2001) <br />' • Data collected from the pump and treat influent and extraction well-head grab ground water <br /> samples were representative of general extracted ground water conditions <br />' One cubic foot of water contains 7 4$ allons conversely, gallon of water is equivalent to <br /> g z Y� one g q <br />' 0 1337 cubic feet, so the volume of processed water is given by <br /> V= (684,501 gallons)(0 1337 ft/gal) =91,518 ft' processed water <br /> IOne gallon of water weighs 8 337 lbs/gal at 60°F, so the mass of processed water is given by <br />' MI.,P =(684,501 gallons)(8 337 lbs /gal) =5,706,685 lbs. processed water <br /> Multiplying the plass of the processed water by the average MTBE concentration (12-06-00 = <br /> 450,ug/L and 01-03-01 = 240 ug/L, avg — 345 /.cg/L) yields the approximate mass of MTBE <br /> removed from processed water <br />' MMraE = (5,706,685 lbs)(0 000000345) = 1.97 lbs MTBE <br /> A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to kilograms of <br /> MTBE <br /> MMTBE= 1 97 lbs MTBE (0 4536 kg/Ib) =894 g of MTBE <br /> I <br /> i <br /> I <br /> • Advanced Geo&2"ronmenW7Inc <br /> I <br />