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Mass--Volume Calculation of Dissolved MTBE - First Quarter 2001 <br /> FLAG CITY CHEVRON- 6421 Capitol Avenue, Lodi, CA <br />' Assumptions <br /> • A total volume of 2,474,726 gallows was extracted from wells EW-2, EW-4, EW-5, EW-6, <br /> EW-7, EW-8,EW-9 and EW-10 between 01 January and 31 March 2001 (based on effluent <br /> flow meter observations between 01 January and 31 March 2001) <br /> • Data collected from the pump and treat influent and extraction well-head grab ground water <br /> samples were representative of general extracted ground water conditions <br /> One cubic foot of water contains 7 48 gallons, conversely, one gallon of water Is equivalent to <br /> 0 1337 cubic feet, so the volume of processed water is given by <br /> V= (2,474,726 gallons)(0 1337 fl/gal) =330,871 W processed water <br /> One gallon of water weighs 8 337 lbs Igal at 60°F, so the mass of processed water is given,by <br /> M.,e,_ (2,474,726 gallons)(8 337 lbs/gal) =20,631,791 lbs. processed water <br /> Multiplying the mass of the processed water by the average MTBE concentration (01-03-01 <br /> 240,ug/L, 02-02-01= 1504g/L and 03-08-01 = 101 ug/L, avg = 164,ug/L) yields the approximate <br /> mass of MTBE removed from processed water <br /> MMTBE_(20,631,791 lbs)(0 000000164) =3.4 lbs MTBE <br /> A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to kilograms of <br /> MTBE <br /> MMTBE= 3 4 lbs MTBE (0 4536 kg/lb) = 1,542 g of MTBE <br /> 1 <br /> Advanced GeoEnvironmentnl,Inc <br />