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ARCHIVED REPORTS XR0004682
Environmental Health - Public
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EHD Program Facility Records by Street Name
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M
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MADISON
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423
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3500 - Local Oversight Program
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PR0544427
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ARCHIVED REPORTS XR0004682
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Last modified
5/7/2019 9:19:40 AM
Creation date
5/7/2019 8:39:48 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
3500 - Local Oversight Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0004682
RECORD_ID
PR0544427
PE
3528
FACILITY_ID
FA0004581
FACILITY_NAME
CHASE CHEVROLET*
STREET_NUMBER
423
Direction
N
STREET_NAME
MADISON
STREET_TYPE
ST
City
STOCKTON
Zip
95203
CURRENT_STATUS
02
SITE_LOCATION
423 N MADISON ST
P_LOCATION
01
P_DISTRICT
001
QC Status
Approved
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SJGOV\wng
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EHD - Public
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' Ground Water Drawdown Test Calculations <br /> Former CHASE CHEVROLET Madison Facility <br /> 423 North Machson Street, Stockton, California <br /> Assumptions <br /> ' • A constant ground water pumping rate of 6 gallons per nunute test conducted on <br /> 24 May 2001 <br /> ' & Wells are screened entirely through the upper water table <br /> • Homogenous ground water aquifer characteristics at observation wells EW-2, MW-19A, <br /> MW-20A and MW-21A and extraction well EW-1 <br /> ' a The Jacobs Straight Line Method (Distance-Drawdown Method can be utilized to <br /> g {� ) <br /> ' calculate hydraulic conductivity,transrrnssivity(T) and storativity yield utilizing draw-down <br /> versus distance on serrn-loganthnvc paper for each well location (Appendix 1) <br /> Where <br /> ' K= hydraulic conductivity <br /> T = transmissivity <br /> ' S = storativrty <br /> Q = constant ground water pumping rate <br /> • <br /> As = draw-down per 1-loganthrmc cycle <br /> ' t= time of pump test <br /> r. = intercept of best fit line with the distance axis <br /> ' b= thickness of aquifer (sem penetrated or exposed) <br /> Calculations ------� <br /> ' Q = 6.0 GPM; As =.1 ft.; t=480 minute; ro =Wit. <br /> �L �6 <br /> -- <br /> T= 70QAs -470(b 0 GPM) —O,�ZS it= tZ/day <br /> ' <br /> 3,9Q-ft'/day x 1 gpd/ft— 4 134 ftz/day apd/ft <br /> S = T(t) — 640 (ro)2= (3,360 ft2/day)(435 nun) — (640)(160)' = 89 G © �� <br /> K= T —b= 25,-O75'gpd/ft —25 feet =j,,063-ft/day <br /> ' 1,0 ft/day(1 cm/sec/2835 ft/day) cm/sec <br /> jo a 00- <br />
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