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Dividing Mg by the weight of one gallon of gasoline, 6.25 lbs/gallon,will yield the volume of gasoline <br /> dissolved into the ground water of the ellipsoid: Y <br /> Veg= (lQ/6.25lb/gal) = 1,490 lbs/6.25 lbs/gal = 238.4 gallons of gasoline <br /> Ground water extraction pilot test removed 1.6 Is/day,therefore 267,670 gallons of impacted water <br /> will at 1,490 lbs gasoline will require approximately 931.25 days or 2.5 years. However, ground <br /> water extraction dynamics, desorption and adsorption, the,duration of total removal may change. <br /> r <br /> i <br /> f <br /> _ k <br />