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Since the gas volume depends on the number of molecules present <br /> the reaction of propane with oxygen produces an increase in <br /> volume The reaction, 1C3H8 + 502 -> 3CO2 + 4H2O, increases the <br /> number of molecules from 6 to 7 per molecule of propane. This <br /> effectively means that after combustion the volume of flow <br /> resulting from the propane is double the propane flow rate . The <br /> reaction of methane (Natural Gas) and oxygen does not produce a <br /> net change in volume, CH4 + 2 02 -> CO2 + 2 H2O, therefore a <br /> correction for combustion does not need to be made when methane <br /> is burned �- <br /> George .L Converse <br /> Geologist <br /> CC <br /> Bruce Tuter <br /> San Joaquin Valley Unified Air Pollution Control District <br /> 4230 Kiernan Ave ##130 <br /> Modesto, CA 95356 <br /> (209) 545-7000 <br /> Mary F Meays <br /> Public Health Services <br /> P 0 Box 2009 <br /> Stockton, California 95201 <br /> (209) 468-0337 <br /> 6al 603 AIR IR RPT 3/08/96 <br />