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The volume must be corrected to standard temperature and <br /> Pressure (STP) <br /> P = Pressure = 14 7 lb/int @ STP <br /> V = Volume c£ <br /> T Temperature in degrees above absolute Zero = 491 . 58OR Q <br /> STP <br /> Using the Ideal Gas Law P1V1/T1 = P2V2/T2 <br /> Solving for V2 =P1V1T2/P2T1 <br /> Assuming PI = P2 = 14 . 7 lb/int , P cancels from the equation <br /> leaving V2 = V1T2/T1 <br /> V1 = Q cf/m x 1440 min/day <br /> T2 = 491 . 580R Tl = 459 58 + TOF at site <br /> V2 = Q cf/min x 1440 min/day x 491 580R/ (459 580 + TOF) <br /> X lb/day = C ug/l x 0 . 0000000621 lb 1/ug cf x Q cf/min x 1.440 <br /> min/day x 491 580R/ (459 580 + TOF) <br /> Q for the Influent sample = The well flow rate . <br /> 6 R603 APPEND. D <br />