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It is possible to calculate the groundwater velocity at a site by calculating the difference in the <br /> . retarded groundwater velocities of two compounds at the site ` <br /> From observation of the first occurrence of mayor compound peaks between MW8 and MW 12, it <br /> is possible to calculate the retard ground water velocities for Benzene and Toluene at this site <br /> Vbenzene =Velocity Benzene <br /> Kbenzene =organic carbon- water partition coefficient (Koc)benzene <br /> Vtoluene Velocity Benzene <br /> Ktoluene=organic carbon- water partition coefficient (Koc) toluene <br /> V=groundwater velocity <br /> Pb= soil density <br /> Oc =organic carbon content <br /> n =porosity <br /> Vc=retarded velocity of a compound= v/(1+(Pb/n*Koc*Oc)) <br /> Since we have two compounds with different retarded velocities flowing under the same conditions <br /> it is possible to solve for the velocity in two simultaneous equations <br /> Vbenzne W v/(1+Pb/n*Kbenzne*Oc) <br /> Vtoluene=v/(1+ (Pb/n*Ktoluene*Oc) <br /> Vbenzene *(1+((pb/n*Oc)*Kbenzene)) = v <br /> Vtoluene * (1+((Pb/n*Oc) * Ktoluene)) =v <br /> The only other unknown in the equation is the product of(Pb/n*Oc) which is not known but Ls the <br /> same for both equations and therefore can be set to the constant X <br /> X=(Pb/n*Oc) <br /> Vbenzene +Vbenzene * Kbenzene X =V <br /> Vtoluene + Vtoluene * Ktoluene X =V <br /> Since both equations are equal to v the groundwater velocity it is possible to set them equal to each <br /> other and solve for X <br /> Vbenzene+ Vbenzene * Kbenzene X =Vtolune+Vtolune * Ktolune X <br /> Vbenzene from first occurrence major peak MW8 to Mw 12 =30.04 feet per year <br /> Kbenzene = 97 <br /> Vtoluene from first occurrence major peak MW8 to Mwl2 =20 74 feet per year <br /> Ktolune =242 <br /> 30.04 + 30 04 * 97 X=20 74 + 20 74 *242 X <br />