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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 25 gals/day <br /> Effluent Stream(N,): 85.00 mg/L-N <br /> Site Area(A): 232 Acres <br /> Concentration Rain NO: 1.00 mg(L-N <br /> Denitrification(d): 20.0% <br /> Deep Perc.of Rain(R): 5.76 in/yr <br /> Result: <br /> Mass Balance(N j: 2.6 mg/L-N <br /> MCL Drinking Water Nitrate as N:Tox mg/L-N <br /> Percent of MCL Nitrate as N 26 <br /> Waste Loading(W): 0.14 in/yr <br /> Equations: <br /> Find(W) <br /> (W) jd = (Q) gal x 1W x 365 day x 1 acre x 12'in x 1 <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A)acre <br /> ' ' .0.03 :b % ,x 3'4<6 p 006Z24 )c Iz x O2f /034y <br /> 0.14 in/yr(site)=25 gat/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre 143,560 sq-ft)x(12 in71 ft)x(1 sole I .32 acres) / <br /> 15-?-b <br /> N,= WN_{1-d)+RNk <br /> W+R Hantzsche-Fennemore Ecuation(NO <br /> ,06 + 5•3b i s 9 _ 2x89 <br /> 2.64 mgrL-N=((0.14 Wyr x 85 mg/L-N x(1-0.2))+(5.76 in7yr x 1mg/L-N))/(0.14 in/yr+5.76 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration(mg/I)of combined effluent and rainfall percolate(2.64 mg/L-N). <br /> W=uniform waste water loading for study area(in/yr)(0.14 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(85 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil(20%). <br /> R=uniform deep percolation of rainfall(5.76 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 85 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 20%. <br /> 3. Estimated deep percolation of rainfall is 5.76 in/yr,see deep percolation of min worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> 1 rerracon <br />