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Nitrate Mass Balance calculation <br /> Data Input: <br /> Effluent Quantity(Q): 788 galsldey Concentration Rain(Nh): 1,00 mg/L-N <br /> EfRuent Stream (NW): 45.91 mg/L-N Denitrification(d); 35.0% <br /> Site Area (A): 9.86 Acres deep Pere, of Rain(R): 4.00 inlyr <br /> Waste Loading (W): 1.07 in/yr <br /> Result: <br /> ` Mass Balance(NG): 7.1 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 71% <br /> +' <br /> Equations: <br /> In = (0) gal x 1 x 365 day x 1_acre x 12 in x L Find <br /> I yr day 7.48 gal 1 year 43,560 fly 1 It (A)acre <br /> 1.071"r(site)=788 gallday x(1 cu-lf l 7.46 gals)x(365 days/7 year)x(7 acre/43,560 sq-ft)x(12 in 9 it)x(1 site/9.96 acres) <br /> N,= WNw(1-d) Rl�ks LLentzsche-Fennemore..Eavition(Nt <br /> W+R <br /> 7.11 mglL-N a((7.07 inlyr x 45.91 mg1L-1V x(1-0.35))+(4 irglyr x 1mg1L-N))41.07 inlyr+4 inlyr) <br /> Variables: <br /> Nc=Average nitrate•N concentration (mgA)of combined effluent and rainfall percolate(7.11 mg/L-N). <br /> W=Uniform waste water loading for study area(inlyr) (1.07 incheslyear). <br /> Nw=Total nitrate-N concentration of waste water percolate(45.91 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soll(31%). <br /> R a Uniform deep percolation of rainfall (4 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions- <br /> 1. Total nitrogen concentration of waste stream based on estimate of 45.91 mg/L-N. <br /> 2, Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 4 intyr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L.N. <br /> i <br /> I <br /> NEIL O, ANDERSON <br /> ^ N D ASSOCIATES <br /> Plate 10 <br />