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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity{C1 788 gals/day Concentration Rain(Nb): 1.00 mg/L-N <br /> Effluent Stream�N,,„): 45.91 mg/L-N Denitrification(d): 35.0% <br /> _ Site Area(A): 9.86 Acres Deep Perc. of Rain (R): 4.00 inlYr <br /> Result: <br /> Mass Balance(Ne): 7.1 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Waste Loading ICM:,1.07 in/yr <br /> Percent of MCL Nitrate as N 71% <br /> Equations: <br /> - find <br /> (W) in = (Q) gal x 1 ft! x 365 day x 1 acre _x-12- x 1 <br /> yr day 7.48 gal 1 year 3;560 ft2 1 ft (A) acre <br /> 4 <br /> 0 in/yr(site) =788 gal/d x(1 cu-ft/7..:48 gals)x(365 days/1 year)x(1 acre 143,560 sq-ft)x(12 in/1 ft)x(1 site/9.86 acres) <br /> Nantzsche-Fennemore E cation Nc <br /> No= WN.,(1-d)+RNb <br /> W+R t7 <br /> 7.11 mg/L-N=((din/yr x 45.91 mg/L-N x(1-0.35))+(4 in/yr x 1mg/L-N))/ rr�r+4 in/y <br /> Variables: <br /> �i Nc=Average nitrate-N concentration (mg/1) of combined effluent and rainfall percolate(7.11 mg/L-N). <br /> i W= Uniform waste water loading for study area (inlyr) (0 inches/year). <br /> � . <br /> Nw=Total nitrate-N concentration of waste water percolate(45.91 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil(35%). <br /> R= uniform deep percolation of rainfall (4 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall (1 mglL-N). <br /> Assumptions: <br /> ' 1. Total nitrogen concentration of waste stream based on estimate of-45.91 mg/L-N. <br /> ! � 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> I 3. Estimated deep percolation of rainfall is 4 inlyr,see deep percolation of rain worksheet. <br /> ; <br /> r -4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> a <br /> t <br /> I <br /> t C <br /> NEIL O. ANDERSON <br /> AND ASSOCI ATES <br /> 1 <br /> Plate 10 <br />