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' Nitrate Mass Balance Calculation <br /> Parcel 1 <br /> Data Input: <br /> Effluent Quantity(Q): 544 gals/day Concentration Rain (Nb): 0.10 mg/L-N <br /> I <br /> Effluent Stream (N,N): 53.00 mg/L-N Denitrification (d): 35.0% <br /> Site Area(A): 1.81 Acres Deep Perc. of Rain (R): 9.00 in/yr <br /> Waste Loading (W): 4.04 in/yr <br /> Result: ! <br /> Mass Balance(NC): 10.7 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N i <br /> Percent of MCL Nitrate as N 107% ! <br /> Equations: <br /> (W) in = (Q) gal x 1 W x 365 day x 1 acre x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A)acre <br /> 4.04 in/yr(site) =544 gal/day x(1 cu-ft/7.48 gals)x(365 days/9 year)x(1 acre 143,560 sq-ft)x(12 in/1 ft)x(1 site/1.81 acres) <br /> N,= WN,(1-d)+RN,, Hantzsche-Fennemore Equation(Nc) <br /> W+R <br /> 10.74 mg/L-N= ((4.04 in/yr x 53 mg/L-N x(1-0.35))+(9 in/yr x 0.1 mg/L-N))1(4.04 in/yr+9 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration (mgll) of combined effluent and rainfall percolate(10.74 mg/L-N). <br /> W= Uniform waste water loading for study area(in/yr) (4.04 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(53 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil (35%). <br /> R= Uniform deep percolation of rainfall (9 in/yr). <br /> Nb= Background nitrate-N concentration of rainfall (0.1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 53 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 9 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 0.1 mg/L-N. <br /> i <br /> I <br /> NEIL O. ANDERSON <br /> A N D A S S O C I A T E S <br /> ! <br /> I <br /> I <br />