Laserfiche WebLink
Nitrate Mass Balance Calculation <br /> Lot 34 <br /> Data Input: <br /> Effluent Quantity(Q): 560 gals/day Concentration Rain(NJ 1.00 mg/L-N <br /> Effluent Stream(N,,): 35.00 mg/L-N Denitrification(d): 25.0% <br /> Site Area(A): 9.68 Acres Deep Perc.of Rain(R): 3.38 in/yr <br /> Waste Loading(W): 0.78 in/yr <br /> Result: <br /> Mass Balance(Nj: 5.7 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N: 57% <br /> Equations: <br /> (W) in = (Q) gal x 1 W x 365 day x 1 acre x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A)acre <br /> 0.78 in/yr(site) =560 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/9.68 acres) <br /> Nc= WN,,,(1-d)+RN„ Hantzsche-Fennemore Eauation(Nc) <br /> W+R <br /> -' 5.72 mg/L-N=((0.78 in/yr x 35 mg/L-N x(1-0.25))+(3.38 in/yr x 1 mg/L-N))/(0.78 in/yr+3.38 in/Yr) <br /> Variables: <br /> _ Nc=Average nitrate-N concentration(mg/1)of combined effluent and rainfall percolate(5.72 mg/L-N). <br /> W= Uniform waste water loading for study area(in/yr)(0.78 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(35 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil(25%). <br /> R=Uniform deep percolation of rainfall(3.38 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 35 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 3.38 in/yr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> "44 NEIL O. ANDERSON <br /> A N D A S S O C I A T E S <br /> Plate 12 <br />