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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 36 day oncentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream ( 5.00 mg/L-N Denitrification (d): 10.0% <br /> Site Are (A): 0. Acres Dep Perc. of Rain (R): 3.54 in/yr <br /> Waste Loading (W): 4.40 in/yr <br /> Result: <br /> Mass Salanc (Nj: 42.8mg/L-N <br /> MCL Drinking Water Nitrat as N: 10.0 mg/L-N <br /> Percent of MCL Nitrat as N 428% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft' x 365 day x 1 acre x 12 in x 1 Find W <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A)acre <br /> 4.4 in/yr(site)=36 ga%day x(1 cu-R/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-R)x(12 in/1 It)x(1 site/0.11 acres) <br /> N,= WN,J1-d)+RN„ Hantzsche-Fennemore Eouation(Nc1 <br /> W+R <br /> 4284 mg/L-N=((4.4 in/yr x 85 mg/L-N x(1-0.1))+(3.54 in/yr x Img/L-N))/(4.4 in/yr+3.54 in/yr) <br /> Variables: <br /> Nc = Average nitrate-N concentration (mg/1)of combined effluent and rainfall percolate (42.84 mg/L-N). <br /> W= Uniform waste water loading for study area (in/yr) (4.4 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(85 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil (10%). <br /> R= Uniform deep percolation of rainfall (3.54 in/yr). <br /> Nb = Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 85 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 10%. <br /> 3. Estimated deep percolation of rainfall is 3.54 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> NEIL O. ANDERSON <br /> A N D A 5 S O C I A T E S <br /> Plate 7 <br />