Laserfiche WebLink
By using the ADF calculated above, the total nitrogen.theoretically produced by the proposed <br /> number of people on-site can be formulated for comparison with the nitrogen applied to the walnut <br /> orchard: 509 gals/day ADF x 3.79 L/gal = 1,929 L/day x 52 mg N/L (after reductions in nitrogen <br /> content) = 100 grams N/day x 314 days/yr = 31.5 kg N/yr x 2.2 lb/kg= 69.3 lbs N/yr_ 11 Acres = <br /> 6.3 lbs N/Ac/yr contributed from potential septic system impact. Even if there were no reductions <br /> assigned to the nitrogen content,this would increase the figure above to approximately 12.6 lbs <br /> N/Ac/yr. <br /> In comparison, Mr. Foppiano applies two, split applications of nitrogen at 50 units (50 lbs N/Ac) in <br /> the spring and mid-summer, for a total of 100 lbs N/Ac/yr. According to the Western Fertilizer <br /> Handbook, this is the correct amount to apply to walnut trees in their current stage of growth. <br /> Additionally, the nitrogen is applied in split applications so that the walnut trees can uptake and <br /> use the nitrogen at two separate times during the growing season. This reduces the likelihood that <br /> excess nitrogen will leach past the root zone. <br /> f <br /> C. SEPTIC SYSTEM COMPONENTS AND NITRATE IMPACT MITIGATION <br /> E <br /> The design of the proposed septic system should be based upon the factors of operation, longevity, <br /> I and environmental protection. The San Joaquin County Environmental Health Department will <br />[ stipulate design requirements for these factors,particularly environmental protection. <br /> SEPTIC TANKS <br /> Septic tanks affect the sludge, scum and effluent volumes, which in turn affect treatment of <br /> nitrogen within the tanks. Typically, the volumetric capacity of septic tanks serving commercial <br />° facilities should be equal to approximately 5 times the Average Daily Flow(5 x 442 = 2210 gals). <br /> In the following equation, the numerical value for pump-out time interval in yrs, times the ADF, <br /> times the peaking value (PF), gives tank capacity required. The peaking value is normally taken to <br /> be 1.5 for commercial projects: <br /> SEPTIC TANK CAPACITY EXAMPLE FOR THE NEW RESTROOM: <br /> Recommended tank capacity for a pump out interval of three yrs: 2.4(QA„E) x Peaking Factor(PF) <br /> = 2.8(509) x 1.5 = 2,138 gal tank capacity required. there are two restrooms that can be used <br /> equally on a theoretical basis; therefore, use one - 2,000 gallon tank for the new septic system. <br /> r <br /> DETENTION TIME EXAMPLE FOR THE NEW RESTROOM: <br /> Detention Time= 2000 gal tank capacity x 0.70 30%volume lost to sludge/scum accumulation) <br /> 1.5 (Peaking factor) x 509 gals/day ^ <br /> Detention Time = 1.83 days. The minimum acceptable detention time is 1.0 day. <br /> 9 <br /> Vafiey AB Research <br /> t <br />