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Three year Pump-out Interval Equation: <br /> 2.8(1,375 gpd ADF)x 1.5 = 5,775 gals <br /> Average Computed Tank Capacity=2,575 +5,775 * 2=4,175 gals <br /> Detention Time Computatio n: <br /> 3,500 gal total tank capacity based on min.detention time x 0.70 f30%volumc lost to sludgeJscum accumulation <br /> 1,375 gpd ADF x 1.5 (Peaking Factor) . <br /> Detention Time= 1.2 days. Therefore a 3,500 anon septic tank is suitable for Sufficient detention time <br /> for the Dry Goods Building. <br /> GUARD/SCALE HOUSE BUILDINGS AND OFFICE TRAILERS <br /> These buildings should have an ADF of no more than 100 gallons per day. Therefore, a Base Tank <br /> Capacity of using a 1,200 gallon septic tank should be sufficient. <br /> LARGE CENTRAL RECEIVING SEPTIC TANK <br /> The size of the large central receiving septic tank can be determined from the total of the ADF's <br /> from each location, and the total of each septic tank volume, also from the four locations. These <br /> r two quantities are then plugged into the Detention Time Equation to check for adequate large tank <br /> size: <br /> Average Daily Florys <br /> Crush Office =918 gpd <br /> Dry Goods = 1,375 gpd <br /> Guard/Scale = 100 gpd <br /> Office Trailers= 100 and <br /> TOTAL =2,493 gpd <br /> I Septic T'cmk Sizes <br /> Crush Office =2,500 gals <br /> Dry Goods =3,500 gals <br /> Guard/Scale = 1,200 gals <br /> Office Trailers= 1,,200 gals <br /> TOTAL =8,400 gals <br /> I <br /> Detention Time Computation: <br /> 8,000 al total tank capacity based on min.detention time x 0.70(30%volume lost to sludee/scum accumulation) <br /> 2,500 gpd ADF x 1.5 (Peaking Factor) <br /> Detention Time= 1.5 days. Therefore, n 8,000 all ank is theoretically suitable for sufficient <br /> detention time for the total anticipated in E nt filo A 9,000 g Ilon tank would give a detention time of <br /> 1.7 days_ <br /> Page 5 of 7 <br /> Chesney Consulting <br />