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Nitrate Mass Balance Calculation 'we <br /> i <br /> Data Input: <br /> Effluent Quantity(Q): 560 gals/da Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream (N,): 4'5.Wm N Denitrification(d): 25.0%✓ <br /> r Site Area(A): 5.00 Acres Deep Pere.of Rain(R): 6.84 in/yr <br /> Waste Loading (W): 1.51 in/yr <br /> Result: <br /> Mass Balance(N°): 6.9 mg/L-N <br /> " MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 69% <br /> ` Equations: <br /> (W) in = (Q) gal x 1 ft' x 365 day x 1 acre x 12 in x 1 Find AAA —� <br /> _ yr day 7.48 gal 1 year 43,560 ft2 1 ft (A) acre <br /> 1.51 in/yr(site) =560 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 x(1 site/5 acres) <br /> N,= WN,.,(1-d)+RN Hantzsche-Fennemore E ua <br /> W+R <br /> 6.91 mg/L-N= 1.51 in/yr x 45 mg/L-N x(1-0.25))+(6.84 in/yr x fmg1L-N))/(1.51 in/yr+6.84 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration (mg/I)of combined effluent and rainfall percolate (6.91 mg/L-N). <br /> W=Uniform waste water loading for study area (in/yr) (1.51 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate 4 m /L-N). <br /> d= Fraction of nitrate-N loss due to denitrification in the so ( %). <br /> R= Uniform deep percolation of rainfall(6.84 in/yr). <br /> _ Nb= Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 45 mg/L-N. <br /> .. 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 6.84 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> NEIL O. ANDERSON <br /> AND ASSOC IATES <br /> r <br /> Plate 10 <br />