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titrate Mass Balance Calculation <br /> Standard Septic System (12.0 Acre Parcel) <br /> Data Input: <br /> Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Quantity(Q): 490 gals/day Denitrification (d): 15.0% <br /> Effluent Stream (NW): 45 mg/L-N Deep Perc. of Rain (R): 5.01 in/yr <br /> Site Area (A): 12.0 Acres Waste Loading (W): 0.55 in/yr <br /> Result: <br /> Mass Balance (N j: 4.7 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 47% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find W <br /> yr day 7.48 qal 1 year 43,560 ft2 1 ft (A) <br /> _ 0.55 in/yr(site) =490 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/12.01 acres) <br /> Nc = WNW(1-d)+RNh Hantzsche-Fennemore Equation (Nc) <br /> W+R <br /> 4.68 mg/L-N= ((0.55 in/yr x 45 mg/L-N x(1-0.15))+(5.01 in/yr x 1 mg/L-N))/(0.55 in/yr+5.01 in/yr) <br /> 21 L13 4 b'F -15 5 4, L- <br /> Y l o <br /> _ Variables: <br /> Nc=Average nitrate-N concentration (mg/1)of combined effluent and rainfall percolate (4.68 mg/L-N). <br /> W = Uniform waste water loading for study area (in/yr) (0.55 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate (45 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil (15%). <br /> R = Uniform deep percolation of rainfall (5.01 in/yr). <br /> Nb = Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 45 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 15%. <br /> 3. Estimated deep percolation of rainfall is 5.01 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> Rs0 <br /> NEIL O.ANDERSON&ASSOC.,INC. <br /> CfOE0ASEVCES-EOINEERNOLA <br /> 2buoLn.Lodi.CA9WV <br /> n(2ffi) 7 ti <br /> s O <br /> Plate 9 <br />