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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 149 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream(N,,): 75.00 mg/L-N Denitrification(d): 25.0% <br /> Site Area (A): 2.5 Acres Deep Perc. of Rain(R): 5.01 in/yr <br /> Waste Loading (W): 0.80 in/yr <br /> _ Result: <br /> Mass Balance(NC): 8.6 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 86% <br /> Equations: <br /> (W) in = (Q) gal x 1 W x 365 day x 1 acre x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ft 2 1 ft (A) <br /> 0.8 in/yr(site) =149 gal/day x(1 cu-ft/7.48 gals) x(365 days/1 year)x(1 acre 143,560 sq-ft) x(12 in/1 ft)x(1 site/2.5 acres) <br /> N, = WN-(1-d)+RN1, Hantzsche-Fennemore Equation(Nc) <br /> W+R <br /> 8.62 mg/L-N=((0.8 in/yr x 75 mg/L-N x(1-0.25))+(5.01 in/yr x 1mg/L-N))/(0.8 in/yr+5.01 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration (mg/1)of combined effluent and rainfall percolate(8.62 mg/L-N). <br /> W= Uniform waste water loading for study area(in/yr)(0.8 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate (75 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil (25%). <br /> R= Uniform deep percolation of rainfall (5.01 in/yr). <br /> Nb = Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 75 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 5.01 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> II No�iton Ln.LOEI, <br /> NEIL O.ANDERSON&ASSOC.,INC. <br /> MOW CMNCAL SM\ACS-EINEERNO LABORATORES <br /> CA 9521OSSOG1709)36].T01 <br /> Plate 9 <br />