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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 850 gaWday Concentration Rain(Nb): 1.00 mgt-N <br /> Effluent Stream(N,); 59.82 mg/L-N Denitrification(d): 30.0% <br /> Site Area(A): 5.00 Acres I Deep Pere.of Rain(R): 5.76 i r <br /> Result: <br /> Mass Balance(N.): 12.6 mgt-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N Waste Loading(W): 229 in/yr <br /> Percent of MCL Nitrate as N 126% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 In x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A)acre <br /> 2.29 in/yr(site)=850 gal/day x(1 cu-ff/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 R)x(1 site/5 acres) <br /> N.= WNL, 1-d)+R& Hanhsche-Fennemore Ecuation(No) <br /> W+R <br /> 12.61 mg/L-N=((2.29 i*r x 59.82 mg/L-N x(1-0.3))+(5.761n/yr x 1mg1L-1V)Y(2.29 UVyr+5.76 in/yr) <br /> Variables: <br /> No=Average nitrate-N concentration(mgA)of combined effluent and rainfall percolate(12.61 mg/L-N). <br /> W=Uniform waste water loading for study area(intyr)(2.29 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(59.82 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil(30%). <br /> R=Uniform deep percolation of rainfall(5.76 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 59.82 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 30%. <br /> 3. Estimated deep percolation of rainfall is 5.76 in/yr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> "44, NEIL O. ANDERSON <br /> AND ASSOCIATES <br /> Plate 2 <br />