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Technical Description <br /> Design example: <br /> A. Equalization tank for 0.05-MGD plant (50,000 gpd)' <br /> B. Average hourly flow (AHF) <br /> 0.05 x 1,000,000 <br /> _12,083 GPH <br /> 24 <br /> C. AHF percentage for consecutive periods of the typical 24-hour day are as follows: <br /> TIME PERIOD % of AHF <br /> 1. 0001-0300 10% <br /> 2. 0300-0600 20% <br /> 3. 0600-0900 70% <br /> L 4. 0900-1200 250% <br /> 5. 1200-1500 150% <br /> 6. 1500-1800 100% <br /> 7. 1800-2100 150% <br /> 8. 2100-0000 50% <br /> D. All flows exceeding average hourly flows must be stored. Tabulate excess flows as follows: <br /> PERIODS % Less Sum of <br /> FIow > 100% AHF 100% Hrs Hourly % <br /> 4 250 150 3 450 <br /> 5 150 50 i 3 150 <br /> 7 150 50 3 150 <br /> Total: 750% <br /> E. Equalization capacity requirement = 7.5 x 2,083 = 15,624 gallons or 31% of average daily <br /> flow. <br /> F. Aeration requirements:Because flow equalization volume may be contained within the batch <br /> reactor, CFM requirements are adjusted as follows: <br /> NORMAL DEMAND <br /> 0.05 x 250 mg/L x 8.34 x 1000 ft' = 72.23 CFM <br /> 1440 <br /> FLOW EQUALIZATION DEMAND , <br /> Criteria: <br /> 5 0,000 gpd flow + 31% = 0.065 MGD <br /> 0.065 x 250 m x 8.34 x 10004' = 94.11 CFM <br /> 1440 <br /> 16 <br />