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Nitrate Mass Balance Calculation <br /> Data Input <br /> Effluent Quantity(Q): 59 gals/day Concentration Rain(No): 1.00 mg/L-N <br /> Effluent Stream (Nj: 70.00 mg/L-N Denitrification (d): 20.0% <br /> Site Area (A): 0.81 Acres Deep Perc. of Rain (R): 11.69 in/yr <br /> Result: <br /> Mass Balance(Nj: 5.3 mg/L-N Waste Loading (W): 0.96 in/yr <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 53% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find <br /> —• yr day 7.48 gal 1 year 43,560 ftz 1 it (A)acre <br /> 0.98 intyr(site) =59 gal/day x (1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre 143,560 sq-ft)x(12 in/1 ft)x(1 site 10.81 acres) <br /> Nc= WN_(1-d)+RN„ Hantzsche-Fennemore Equation(Nc) <br /> W+R <br /> 5.25 mg/L-N= ((0.98 intyr x 70 mg/L-N x(1-0.2))+(11.69 in/yr x 1mg/L-N))/(0.98 in/yr+11.69 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration (mg/1)of combined effluent and rainfall percolate (5.25 mg/L-N). <br /> W=Uniform waste water loading for study area(intyr) (0.98 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(70 mg/L-N). <br /> d= Fraction of nitrate-N loss due to denitrification in the soil(20%). <br /> R= Uniform deep percolation of rainfall (11.69 in/yr). <br /> 0 <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 70 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 20%. <br /> 3. Estimated deep percolation of rainfall is 11.69 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> NEIL O. ANDERSON <br /> A N D A S S O C I A T E S <br /> Plate 10 <br />