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ARCHIVED REPORTS_XR0003759
Environmental Health - Public
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EHD Program Facility Records by Street Name
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HAZELTON
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375
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2900 - Site Mitigation Program
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PR0540905
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ARCHIVED REPORTS_XR0003759
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Last modified
2/3/2020 9:32:03 PM
Creation date
2/3/2020 9:01:19 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0003759
RECORD_ID
PR0540905
PE
2960
FACILITY_ID
FA0023406
FACILITY_NAME
SIERRA LUMBER MANUFACTURERS
STREET_NUMBER
375
Direction
W
STREET_NAME
HAZELTON
STREET_TYPE
AVE
City
STOCKTON
Zip
95205
APN
147120808
CURRENT_STATUS
01
SITE_LOCATION
375 W HAZELTON AVE
P_LOCATION
01
QC Status
Approved
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SJGOV\sballwahn
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EHD - Public
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Mass-Volume Calculations Of Extracted Gasoline Hydrocarbons <br /> • SIERRA LUMBER-375 West Hazelton Avenue, Stockton, CA <br /> Assumptions <br /> I Utilizing analytical data collected from air samples (Table 4) and from field measurements collected during <br /> the SVE pilot test(Table 5), the average concentration of extracted gasoline hydrocarbons at the site can be <br /> approximated. <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C • Q • t _ <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kghn3) <br /> Q=extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> I1. 10 January to 21 February 2002 <br /> I . The average analytical TPH-g concentration for this time interval was determined to be 310µg/l(01-10-02=310,sg/L <br /> and 02-21-02=310µg/L, avg =310µg/L) The average flow rates during this time was calculated at 0 33 inches of <br /> water or approximately 32 cubic feet per minute(table 5), the operational period was equal to 1,008 hours of running <br /> I <br /> time <br /> C = 310µg/1=0 000310 kg/m' <br /> Q = 0 33 inches water= 32 ff/nun <br /> t= 1,008 hours <br /> Converting Q to in'/hour yields <br /> I Q=(32 Omni)•(60 min/hour) •(0 0283168m3/ft)=54 37 m' <br /> /hour <br /> M=C • Q• t=(0 000310 kg/m3) •(54 37 m'/hour) • (1,008 hours)= 16 99 kg of gasoline <br /> IConverting kg of gasoline to pounds of gasoline yields <br /> I16 99 kg of gas • 2 2046 lbs of gas/kg of gas=37 46 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> I37 46 lbs of gas • 0 16 gal of gas/lbs of gas �c 5.99 gallons of gasoline <br /> I <br /> I <br />
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