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Adsorbed Mass-Volume Calculations (continued)
<br /> SIERRA LUMBER- 375 West Hazelton Avenue, Stockton, CA
<br /> yields approximately 45,796,836 cm' Using 1 5 g/cm2 as the weight of soil, the total weight of contaminated soil is
<br /> approximately 68,695,254 Using 7,500 ppm as the"average"concentration of gasoline in the inner-middle sequence
<br /> yields 515,214 grams of gas Converting grams of gasoline to volume of gasoline(gallons)using density of gasoline
<br /> to equal 0 74 yields 696,236 cm3 Dividing by 3,785 gallons per cm3 yields 184 gallons of gasoline
<br /> 3) Approximate volume of petroleum hydrocarbon impacted soil in middle sequence(V,,,)
<br /> VM=(42 ft)(35 ft)(0 7854)(1/316 ft) -! 6,158 ft'(lyd'/27ft')= 228 yd'
<br /> The volume of the middle sequence(Vm) should be subtracted from the overall volume of the inner-middle sequence
<br /> (VM)
<br /> VM -VM-V,,,, -4 228 yd'-94 5 yd' 4 134 yd'
<br /> The volume of the inner middle sequence can be calculated by the method shown above Converting 134 yd to cm'
<br /> yields approximately 102,111,568 cm3 Using 1 5 g/cm'as the weight of soil, the total-Aeight of contaminated soil is
<br /> approxunately 153,167,352 g Using 3,000 ppm as the"average"concentration of gasoline in the middle sequence yields
<br /> 459,502 grams of gas Converting grams of gasoline to volume of gasoline(gallons) using density of gasoline to equal
<br /> 0 74 yields 620,949 cm3 Dividing by 3,785 gallons per cm'yields 164 gallons of gasoline
<br /> 4) Approximate volume of petroleum hydrocarbon impacted soil in outer-middle sequence(Vo,,,)
<br /> VO,=(57 ft)(45 ft)(0 7854)(1/319 ft) -1 12,759 ft' (lyd'/27ft3)= 473 yd'
<br /> The volume of the outer-middle sequence(Vo,,,) should be subtracted from the overall volume of the middle sequence
<br /> (VM)
<br /> VOM —VoM-VM -4 473 yd'-228 yd' -+245 3 d'
<br /> The volume of the inner middle sequence can be calculated by the method shown above Converting 245 ydto cm3
<br /> yields approximately 186,971,126 cm' Using 1 5 g/cm' as the weight of soil, the total weight of contaminated soil is
<br /> approximately 280,456,689 g Using 550 ppm as the"average"concentration of gasoline in the outer-muddle sequence
<br /> yields 154,251 grams of gas Converting grams of gasoline to volume of gasoline(gallons)using density of gasoline
<br /> to equal 0 74 yields 208,448 cm3 Dividing by 3,785 gallons per cm'yields 55 gallons of gasoline
<br /> 5) Approximate volume of petroleum hydrocarbon impacted soil in outer sequence (Vo)
<br /> Vo=(67 ft)(55 ft)(0 7854)(1/x25 ft) -0 24,118 ft'(1yd'/27ft3)4 893 yd'
<br /> The volume of the outer-middle sequence(V,,,)should be subtracted from the overall volume of the outer sequence(Vo)
<br /> Vo =VO-VoM -i 893 yd'-473 yd' -t►420 yd'
<br /> The volume of the inner middle sequence can be calculated by the method shown above Converting 420 yd'to cm3
<br /> yields approximately 321,320,461 cm' Using 1 5 g/cm3 as the weight of soil, the total weight of contaminated soil is
<br /> I approximately 481,980,692 g Using 50 ppm as the"average"concentration of gasoline in the outer-middle sequence
<br /> yields 24,099 grams of gas Converting grams of gasoline to volume of gasoline (gallons)using density of gasoline to
<br /> equal 0 74 yields 32,566 cm' Dividing by 3,785 gallons per cm' yields 9 gallons of gasoline Combmmg the total
<br /> volume of gasoline impacted soil yields a grand total of 893 yd3 containing an estimated 613 gallons of gasoline
<br /> Advanced GeoEnvironmental,Inc
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