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ARCHIVED REPORTS_XR0003808
Environmental Health - Public
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EHD Program Facility Records by Street Name
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HAZELTON
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2900 - Site Mitigation Program
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PR0540905
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ARCHIVED REPORTS_XR0003808
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Last modified
2/3/2020 9:43:46 PM
Creation date
2/3/2020 9:20:19 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0003808
RECORD_ID
PR0540905
PE
2960
FACILITY_ID
FA0023406
FACILITY_NAME
SIERRA LUMBER MANUFACTURERS
STREET_NUMBER
375
Direction
W
STREET_NAME
HAZELTON
STREET_TYPE
AVE
City
STOCKTON
Zip
95205
APN
147120808
CURRENT_STATUS
01
SITE_LOCATION
375 W HAZELTON AVE
P_LOCATION
01
QC Status
Approved
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SJGOV\sballwahn
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EHD - Public
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1 <br />' Mass-Volume Calculations Of Extracted Gasoline Hydrocarbons <br /> • SIERRA LUMBER-375 West Hazelton Avenue, Stockton, CA <br />' Assumptions <br />' Utilizing analytical data collected from air samples (Table 6) and from field measurements collected daring <br /> SVE remediation(Table 7), the average concentration of extracted gasoline hydrocarbons at the site can be <br /> approximated <br />' The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C • Q•t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m3) <br />' Q=extraction flow rate(rn/hr) <br /> t=operational period(hrs) <br />' The average inlet TPH-g concentration and average flow rates during each tune interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br />' 1. 09 October 2003 to 18 November 2003 <br />'. The average analytical TPH-g concentration for this tune'mterval was determined to be 430,ug/l(10-09-03 =50'Ug/l <br /> and 11-18-03 =810 pg/L, avg =430 jzg/L) The average flow rates during this time was calculated at 0 25 inches of <br /> water or approximately 28 cubic feet per mmute(table 7),the operational period was equal to 960 hours of running time <br />' C = 430,ug/l=0 000430 kg/m' <br /> Q z 0 25 inches water = 28 fti/min <br /> I t=960 hours(40 days operation) <br /> Converting Q to m`/hour yields <br /> Q=(28 ft/min) •(60 mui/hour)•(0 0283168m/fl3)=47 57 n2fhour <br /> M=C • Q • t=(0 000430 kg/m')•(47 57 m3/hour)• (960 hours)= 19 64 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 19 64 kg of gas• 2 2046 lbs of gas/kg of gas=43 3 lbs of gasoline <br /> 43 3 lbs gas/41 days=1 06 lbs/day <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 43 3 lbs of gas • 0 16 gal of gas/lbs of gas = 6.93 gallons of gasoline <br /> I <br />
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