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ARCHIVED REPORTS_XR0012454
Environmental Health - Public
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2900 - Site Mitigation Program
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PR0505714
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ARCHIVED REPORTS_XR0012454
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Last modified
3/4/2020 9:46:12 AM
Creation date
3/4/2020 9:36:10 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0012454
RECORD_ID
PR0505714
PE
2950
FACILITY_ID
FA0003590
FACILITY_NAME
M B P
STREET_NUMBER
501
Direction
W
STREET_NAME
LODI
STREET_TYPE
AVE
City
LODI
Zip
95240
APN
03731045
CURRENT_STATUS
02
SITE_LOCATION
501 W LODI AVE
P_LOCATION
02
P_DISTRICT
004
QC Status
Approved
Scanner
SJGOV\sballwahn
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EHD - Public
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MASS CALCULATIONS OF <br />' EXTRACTED HYDROCARBONS (Gasoline) <br /> Mel Bokides Petroleum, Inc. <br /> 501 W. Lodi Avenue, Lodi, California <br /> The hydrocarbon mass removed during the operating period can be calculated using the following <br />' equation: M= C•Q•t <br />' where: M= cumulative mass recovered (kg) <br /> C = vapor concentration (kg/m3) <br /> Q = extraction flow rate (m3/hr) <br /> t = operational period (hrs) <br /> The calculation for the first time period is provided as an example for the determination of mass/ <br /> volume of hydrocarbons removed over the reporting period. <br /> 03-19-02 to 04-15-02 <br /> using: C= 110 gg/l+ 110 gg/ll2= 0.00011 kg/nn <br /> Q= 56 scfrn(average) =94 m'/hr <br />' t = 15.7 hours (sum of known operation) <br /> 0.00011 kghrI - 94 nPhr • 15.7 hours =0.16 kg of gasoline <br />' • 0.16 kg of gasoline • 2.2046 lbs/kg= 0.35 lbs of gasoline <br /> to convert lbs of gasoline to gallons of gasoline, use 0.16 gal/lbs: <br /> 0.35 lbs of gal • 0.16 gal/lbs = 0.056 gallons of gasoline <br /> 0445-02 to 05-06-02 <br /> using: C = 110 1ig/1+ 380 �Lg/l/2 = 0.000245 kg/rrl <br /> ' Q= 69 scf n(average) = 116 m3/hr <br /> t = 502 hours (sum of known operation) <br /> ' 0.000245 kgW • 116 nPhr • 502 hours= 14.3 kg of gasoline <br /> 14:3 kg of gasoline • 2.2046 lbs/kg= 31.4 lbs of gasoline <br /> to convert lbs of gasoline to gallons of gasoline, use 0.16 gal/lbs: <br /> 31.4 lbs of gal • 0.16 galllbs = 5 gallons of gasoline <br /> ' 05-06-02 to 06-03-02 <br /> using: C= 360 pg/1+ 380 Vg/l/2 = 0.00037 kg/In3 <br /> Q= 67 scfm(average)= 113 z Pby <br /> t = 668 hours (sum of known operation) - <br /> 0.00037 kg/m3 • 113 rn3/hr • 668 hours =27.9 kg of gasoline <br /> 27.9 kg of gasoline • 2.2046 lbs/kg= 61.5 lbs of gasoline <br /> to convert lbs of gasoline to gallons of gasoline, use 0.16 gal/lbs: <br /> 61.5 lbs of gal • 0.16 gal/lbs =9.8 gallons of gasoline <br /> ' Approximately 42kg, 93 lbs or 14.5 gallons gasoline removed between March and June 2002 <br /> On average 1 lbs of gasoline were removed each day of operation. <br /> Advanced CeoEnvironme=4Inc. <br />
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