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Calculation of Mass of Contaminants <br /> thickness x area= volume <br /> volume x density = total mass of soil <br /> total mass of soil x concentration = mass of contaminants <br />' DSS Model <br /> Density of soil = 1.5 g/cm3 (approximately 1.26 tons/yard) <br /> 0, <br /> 1 <br /> to 18 (clay and sandy clay)samples Line 1 @ 6', B I-15 and VE 1-15,. <br /> 18' to 38' (clayey gravel) samples B1-30', VEl- 25', B2-20' and 132-25'. as <br /> 38' to 55' (sand) samples B1-45' and VE-40' <br />' DSS Model Example Calculation, Layer 1- benzene <br /> f'$ 5,S <br /> Ci@feet x 0.3048 m/ft=6.7 meters thickness <br /> 6.7 m x 8 m wide x 8 m length =430-m3 volume <br /> 4.3 x 108 cm'volume <br /> -4 3 x 108 cm3 x 1.5g/cm3 =-6-4"x 10 e grams of soil <br /> 15,3 =6:4"x 10 'kg soil' r,,3 674-x I OS kg of soil x 96 mg/kg(benzene) =,64X 10 7 mg of benzene <br /> =62-kg of benzene <br /> 53 <br /> @ DSS Model Example Calculation, Layer 2 - benzene <br /> (0,1 <br /> 20 feet x 0.3048 m/ft=yl'meters thickness <br />' 6.1 m x 8 m wide x 8 m length =390 m3 volume <br /> =3.9 x 108 cm3 volume <br /> 3.9 x I0'cm3 x 1.5g/cm3 =5.85 x 10'grams of soil <br /> =5.85 x 10 'kg soil <br /> 5.85 x 105 kg of soil x 11 mg/kg(benzene) =6.4 x 10 6 mg of benzene <br /> 2 =6.4 kg of benzene <br /> DSS Model Example Calculation, Layer 3 - benzene <br /> 17 feet x 0.3048 m/ft=ammeters thickness <br />' 5.2 m x 8 m wide x 8 m length =333 m3 volume <br /> =3.3 x 10 a cm3 volume <br />' 3.3 x 10 'cm3 x 1.5g/cm3 =5.0 x 10 a grams of soil 5 <br /> =5.OxlOSkgsoil 165 )( 10 <br /> 5.0 x I0'kg of soil x-0-04-mg/kg(benzene) = I.9 x 10'mg of benzene <br /> !+7 <br /> =0.019 kg of benzene <br /> 0 0 a ao .. . <br /> • <br />