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HYDROCARBON-WACTED SOIL <br /> ' VOLUME ASSUMPTIONS AND CALCULATIONS (CONTINUED) <br /> 3) (45-feet through 50-feet) The average concentration yields approximately 39 85 ppm <br /> Using 39 85 parts per million as the average concentration of gasoline, the volume of gasoline is <br /> weight of soil • average concentration -4 2,015,777,122 g - 0 00003985 = 80,329 g of gasoline <br /> Converting grams of gasoline to volume of gasoline(gallons) using density of gasoline to equal 0 8 <br /> 80,329 g of gasoline-- 0 8cm3/g = 100,410 9 cm3 <br /> 100,410 9 cm3 • (1 gallon — 3,785 cm3) = 26 53 gallons of gasoline <br /> 4) (50-feet through 55-feet) The average concentration yields approximately 2 78 ppm <br /> Using 2 78 parts per million as the average concentration of gasoline, the volume of gasoline is <br /> weight of soil • average concentration -4 2,015,777,122 g • 0 00000278 = 5604 g of gasoline r <br /> Converting grams of gasoline to volume of gasoline (gallons) using density of gasoline to equal 0 8 <br /> ' 5,604 g of gasoline — 0 8cm3/g = 7,0048 cm3 <br /> ' 7,004 8 cm3 • (1 gallon— 3,785 cm3) z 1.85 gallons of gasoline <br /> ' S) (55-feet through 60-feet) The average concentration yields approximately 2 78 ppm <br /> Using 2 78 parts per million as the average concentration of gasoline, the volume of gasoline is <br /> ' weight of soil • average concentration -4 2,015,777,122 g • 0 00000278 = 5604 g of gasoline <br /> ' Converting grams ofgasohne to volume of gasoline (gallons) using density of gasoline to equal 0 8 <br /> 5,604 g of gasoline— 0 8cm3/g = 7,0048 cm3 <br /> 7,0048 cm3 • (1 gallon— 3,785 cm3) = 1.85 gallons of gasoline <br /> ' Adding the total gallons of gasoline from 1 through 5 yields <br /> 79.89 + 106.41 + 26.53 + 1.85+ 1.85 = 216.53 gallons of gasoline <br /> 1 <br /> _ 1 <br />