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' Volume to Mass Calculation of Dissolved Benzene <br /> Multiplying the volume of water as liters by the average Benzene concentration (500 41) yields the <br /> approximate mass of dissolved benzene remaining in the ground water <br /> ' K=e„e= (1,556,522 5 liter of water)(500pg/1)= 778,261,250 or 7 8 x 108micrograms <br /> M4e,,ene as grams= 778 26 grams <br /> A.....ne as kilograms= 0 778 kilograms <br /> ' <br /> Multiplyingthe volume of water as liters b the average TPH- concentration (5,000 µg11) yields the <br /> Y g g <br /> approximate mass of dissolved TPH remaining in the ground water <br /> 1 Mbenzcne = (1,556,522 5 liter of water) (5' ��)000 1 7782,612,500 or 7 8 x 109micro ams <br /> Mbenz,,,as grams= 7782 6 grams <br /> ' M..fe as kilograms= 7 78 kilograms <br /> 1 <br /> 1 <br /> 1 <br /> I <br /> 1 <br /> Advanced GcoEnvironmental,Inc <br />