ARCHIVED REPORTS_XR0006081 - Laserfiche WebLink

Home Browse Search

1 2) Approximate volume of petroleum hydrocarbon impacted soil in cone#2(V. Vo=(3 14)(14 ft)2(l/2(23 ft)) -+7,081 1 ft' (lyd3/27ft3) = 262.3 yd3 Converting 262 3 yd3 to cm3 (i e lyd3 = 764,555cm3) yields approximately 200,542,776 5 cm3 Using 16 g/cm3 as the weight of soil, the total weight of contaminated soil is approximately ' 320,868,442 4 g Using the 4 1 mg/kg as the"average"concentration of gasoline in the cone,the volume of gasoline ' Is weight of soil• average concentration -*320,818,604 7 g•4 1x10'=1,315 6 g of gasoline ' Converting grams of gasoline to volume of gasoline (gallons) using density of gasoline to equal 0 75 g/cm3 ' 1,315 6 g of gasoline-- 0 75 g/cm3 = 1,754 cm3 1,754 crn3 • (1 gallon- 3,785 cm3) = 0.463 gallons of gasoline ' 3) Approximate volume of petroleum hydrocarbon impacted soil in sphere#3(Vo) ' V.=4/3 (3 14)(3 ft)' 4113 ft' (lyd3/27ff3) = 4,186 yd3 Converting 4 186 yd3 to cm3(i e lyd3=764,555cm3)yields approximately 3,200,936 cm3 Using ' 16 g/cm3 as the weight of soil,the total weight of contaminated soil is approximately 5,121,498 g Using the 12 mg/kg as the"average"concentration of gasoline in the cone,the volume of gasoline ' I5 weight of soil • average concentration -+ 5,121,498 g• 1 2 x1V =6 145 g of gasoline ' Converting grams of gasoline to volume of gasoline (gallons) using density of gasoline to equal 0 75 g/cm ' 6 145 g of gasoline -0 75 g/cm3=8 19 cm3 ' 8 19 cm3 • (1 gallon- 3,785 cm) = 0.002 gallons of gasoline 4) Approximate volume of petroleum hydrocarbon impacted soil in cone#4(V,) Vo=(3 14)(5 ft)2(1/2(10 ft)) -4392 69 ft3 (lyd3/27ft3) 14.53 yd3 Converting 14 53 yd3 to cm3 (i e lyd3 = 764,555cm3) yields approximately 11,108,984 15 cm3 Using 16 g/cm3 as the weight of soil, the total weight of contanunated soil is approximately • 17,774,374 64 g Advanced GeoEnvironment4 Inc.