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Seismic Forces <br /> Calculating Seismic Forces <br /> From 2006 International Building Code,ACE 7-05 <br /> generic calx <br /> Units Comments <br /> Shear(lateral movement) <br /> V Base Shear <br /> W Non bldg structure operating weight-tank&contents <br /> Soy=2/3 SMS Equation 11.4-3 <br /> V=0.305D5WI Sections 15.7.6 a. And 15.4.2 <br /> 1=Importance Factor 1 IBC Section 1604.5--not a bldg that represents substantial <br /> hazard to human life in event of failure,and not bldg <br /> designated as essential facility <br /> F, Short period site coefficient(at 0.2 period) <br /> SMS=F.Ss (11.4-1) <br /> Max SDs=2/3 Max S, <br /> Max V=.30(Max SDs)Wl <br /> Overturning <br /> h= ft lbs <br /> Overturning moment=V'h/2 ft lbs <br /> Resisting moment due to weight of tank and contents= <br /> W'w/2 ft lbs Weight of tank and contents times 1/2 width <br /> Assume uplift=2/3 V Ib <br /> then effective weight=W-2/3V Ib <br /> Resisting moment due to weight of tank and contents= ft lbs <br /> (W-2/3V)`w/2 <br /> Including Friction in shear calculation <br /> V=Coefficient of Friction <br /> Fr=Friction Force <br /> N=normal force=W <br /> Fr=µN <br /> then Fr= N(W-2/3V) <br /> Net base shear=V-Fr <br /> p =0.45 for concrete-steel <br /> Net base shear=V-.45'(W-2/3V) <br /> Note friction will not be considered in seismic <br /> calculations for this site <br />