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i <br /> i <br /> MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> iAssumptions <br /> • Utilizing analytical data collected from air samples(Table 5)and from field measurements collected during the <br /> i SVE pilot test (Table 6), the volume and mass of extracted gasoline hydrocarbons at the site can be <br /> approximated <br /> iThe hydrocarbon mass-volume removed during the operating period can be calculated using the following equation <br /> M=C• Q • t <br /> iwhere M= cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m'/hr) <br /> it=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br /> i approximate mass/volume of extracted gasoline hydrocarbons <br /> i23 September to 22 December 2004 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 820 µg/1(09/23/04= <br /> i• 1400µg/1, 10/22/04=980µg/1, 11/22/04=580µg/1, 12/22/04=320µg/1,avg =820µg/1) The average flow <br /> rate was calculated at 2 0 inches of water, or approximately 74 cubic feet per minute (nomograph), the <br /> operational period was equal to 2,160 hours of running time(Table 6) <br /> iC = 820 µg/1=0 000820 kg/m' <br /> Q = 2 0 inches water z 74 ft3/mm <br /> I t=2,160 hours <br /> Converting Q to m3/hour yields <br /> IQ=(74 ft3/min)•(60 mm/hour)•(0 0283168m3/ft) = 125 7 m'/hour <br /> M=C • Q•t=(0 000820 kg/m 3)•(125 7 m3/hour)• (2,160 hours)=222 6 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 222 6 kg of gas•2 2046 lbs of gas/kg of gas=491 lbs of gasoline <br /> Convening puunda of gaauluie to gaiions of gasoiute yields <br /> 491 lbs of gas •0 16 gal of gas/lbs of gas = 78 6 gallons of gasoline <br /> I <br /> Advanced GeoEnvironmental,Inc <br />