Laserfiche WebLink
i <br /> MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> IAssumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE pilot test(Table 5), the volume of extracted gasoline hydrocarbons at the site can be approxunated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C• Q• t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br /> 26 September 2002 to 17 December 2002 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 1,620 pg/1 <br /> g/1(09-26-02=950µg/1, 10-24-02=1,600 µg/l, 11-12-02=3,400 µg/1 and 12-17-02=530, avg = 1,620 µg/1) <br /> I The average flow rate was calculated at 3 2 inches of water or approximately 98 cubic feet per rrunute <br /> (nomograph),the operational period was equal to 2,102 hours of running time(Table 7) <br /> C z 1,620 µg/1=0 001620 kg/m3 <br /> Q = 3 2 inches water = 98 ft/mm. <br /> t=2,102 hours <br /> Converting Q to&/hour yields <br /> Q=(98 ft loon)•(60 nun/hour) •(0 0283168m/f33)= 166 5 r0hour <br /> IM=C• Q •t (0 001620 kg/m') •(166 5 &/hour)• (2,102 hours)=567 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> I567 kg of gas• 2 2046 lbs of gas/kg of gas= 1,250 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 1,250 lbs of as • 0 16 al of as/lbs of as = 200 gallons of gasoline <br /> g g g g g <br />