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MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> Assumptions: <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE pilot test(Table 5),the volume of extracted gasoline hydrocarbons at the site can be approximated. <br /> t :The hydrocarbon mass removed during the operating period can be calculated using the following equation: <br /> 4 . <br /> M=C*Q • t <br /> where: -M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/rn3) <br /> Q=extraction flow rate(m3/hr) <br /> t=operational period(hrs) <br /> The average inlet TPH- <br /> g g concentration and average flow rates during each time interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons. <br /> I <br /> I I June 2002 to 26 September 2002 <br /> f 1) The average analytical TPH-g concentration for this time interval was determined to be 548µg/l g/l(06-11-02= <br /> 500µg/l,07-17-02=210µg/i,08-19-02=530µg/1 and 09-26-02=950;avg.=548 µgll).The average flow rate <br /> was calculated at 3.2 inches of water or approximately 98 cubic feet per minute(nomograph);the operational <br /> period was equal to 2,118 hours of running time(Table 6). <br /> C = 548 µg/1=0.000548 kg/m' <br /> Q z 3.2 inches water z 98 if/rain <br /> t=2,118 hours k <br /> Converting Q to m3/hour yields: <br /> Q_(98 if/min)•(60 rain/hour) •(0.0283168m'/ft')= 166.5 m3/hour <br /> F <br /> �* M=C• Q • t=(0.000548 kg/m')•(166.5 m3/hour)• (2,118 hours)= 193 kg of gasoline V s <br /> Converting kg of gasoline to pounds of gasoline yields: r <br /> L193 kg of gas • 2.2046 lbs, of gas/kg of gas=426 lbs of gasoline <br /> 5 Converting pounds of gasoline to gallons of gasoline yields: <br /> 426 lbs. of gas • 0.16 gal of gas/lbs. of gas 68.2 gallons of gasoline } <br /> { <br />