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MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> Assumptions <br /> Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE pilot test(Table 5), the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the o eratmgPeriod can be calculated using the following equation <br /> M=C• Q • t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m3/hr) <br /> t=operational period(hrs) <br /> IThe average unlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br /> 11 March 2002 to 11 June 2002 <br /> 1) The average analytical TPH-g concentration for this tune interval was determined to be 428µg/l g/1(03-11-02= <br /> 520µg/1,04-15-02=350 ug/1,05-13-02-340 µg/1 and 06-11-02=500, avg =428 µg/1) The average flow rate <br /> . was calculated at 3 2 inches of water or approximately 98 cubic feet per minute(nomograph),the operational <br /> Iperiod was equal to 2,208 hours of running time(Table 6) <br /> C = 428 µg/l=0 000428 kg/ma <br /> I Q = 3 2 inches water = 98 ft/mm <br /> t=2,208 hours <br /> Converting Q to m/hour yields — <br /> Q=(98 fl/mm)•(60 mm/hour)•(0 0283168m'/ft') 166 5 m3/hour <br /> IM=C • Q • t=(0 000428 kg/m')•(166 5 m/hour)• (2,208 hours)= 157 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> I157 kg of gas• 2 2046 lbs of gas/kg of gas =347 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 3Y7 iub of gas = v i U gal of gaw 1U., Gf gas ✓a 4 r5 i11wiaa W1 gasoline <br /> t <br /> I <br />