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iVOLUME-MASS CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE pilot test (Table 5), the volume and mass of extracted gasoline hydrocarbons at the site can be <br /> approximated <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the following equation <br /> M=C • Q • t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m3) <br /> Q=extraction flow rate(m3/hr) <br /> It=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br /> Iapproximate mass/volume of extracted gasoline hydrocarbons <br /> 30 December 2003 to 24 March 2004 <br /> 1) The average analytical TPH-g concentration for this tune interval was determined to be340 µg/l (12-30-03= <br /> . 760µg/1,01-26-04=220µg/1,02-23-04=330µg/1&03-24-04=<50µg/1, avg =340µg/1) The average flow <br /> rate was calculated at 2 1 inches of water or approximately 71 cubic feet per minute (nomograph), the <br /> operational period was equal to 2,040 hours of running tune(Table 6) <br /> C = 340µg/1=0 000340 kg/m3 <br /> Q z 2 1 inches water = 71 ff'/nun <br /> t=2,040 hours <br /> Converting Q to m3/hour yields <br /> Q=(71 ft/min) •(60 nun/hour) •(0 0283168m'/ft)= 120 6 m/hour <br /> M=C •Q• t=(0 000340 kg/m') •(120 6 m'/hour) • (2,040 hours) =83 65 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 83 65 kg of gas • 2 2046 lbs of gas/kg of gas= 184 4 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 184 4 lbs of gas • 0 16 gal of gas/lbs of gas = 29 5 gallons of gasoline <br /> i <br /> • advanced GeoEnvironrnental,Inc <br />