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i <br /> iVOLUME-MASS CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> Assumptions <br /> i • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE pilot test (Table 5), the volume and mass of extracted gasoline hydrocarbons at the site can be <br />' approximated <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the following equation <br /> M=C• Q • t <br /> i <br /> where M=cumulative mass recovered(kg) <br />' C=vapor concentration(kg/m3) <br /> Q=extraction flow rate(m3/br) <br /> t=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each tune interval were utilized for calculating the <br />' approximate mass/volume of extracted gasoline hydrocarbons <br /> 09 September 2003 to 30 December 2003 <br />' 1) The average analytical TPH-g concentration for this time interval was determined to be2,240µg/1(09-09-03= <br /> 2,600 µg/l, 10-09-03= 3,200 µg/1, 11-18-03— 2,400 µg/l & 12-30-03= 760 µg11 , avg = 2,240 µg/1) The <br /> lieaverage flow rate was calculated at 2 7 inches of water or approximately 86 cubic feet per minute(nomograph), <br /> the operational period was equal to 1,745 hours of running time(Table 6) <br /> C = 2,240µg/1=0 002240 kg/m} <br />' Q = 2 7 inches water = 86 ft3/nun <br /> t= 1,745 hours <br />' Converting Q to m'/hour yields <br /> Q=(86 ft3/mm) •(60 min/hour)•(0 0283168m3/ft3)= 146 1 m'/hour <br />' M=C• Q• t=(0 002240 kg/m3) •(146 1 m3/hour)• (1,745 hours)=571 kg of gasoline <br /> Convertmg kg of gasoline to pounds of gasoline yields <br /> 1 571 kg of gas• 2 2046 lbs of gas/kg of gas=1,259 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 1,259 lbs of gas • 0 16 gal of gas/lbs of gas = 201 gallons of gasoline <br /> 1 <br /> 1/ <br /> f0 Advarxcf d GeoEnv►ronmental,Inc <br /> i <br /> 1 <br />