Laserfiche WebLink
I <br />' VOLUME-MASS CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br />' Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br />' SVE pilot test (Table 5), the volume and mass of extracted gasoline hydrocarbons at the site can be <br /> approximated <br />' The hydrocarbon volume-mass removed during the operating period can be calculated using the tifollowmg equation <br /> M=C• Q • t <br />' where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m3) <br /> Q=extraction flow rate(m'/hr) <br />' t=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br />' approximate amass/volume of extracted gasoline hydrocarbons <br />' 23 June 2003 to 09 September 2003 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be798 µg/1 (06-23-03= <br />' • 200 gg/1,07-24-03=210µgll,08-13-03=180µg/1&09-09-03=2,600 gg/l,avg =798 gg/1) T'he average#low <br /> rate was calculated at 3 9 inches of water or approximately 101 cubic feet per minute (nomograph), the <br /> operational period was equal to 1,877 hours of running time(Table 6) <br />' C = 798 µg/1=0 000798 kg/m' <br /> Q = 3 9 inches water = 101 ft3/min <br /> t= 1,877 hours <br />' Converting Q to m'/hour yields <br /> Q=(101 ft3/mm) •(60 mm./hour) •(0 0283168rn/f1') = 171 6 m'/hour <br />' M=C• Q• t=(0 000798 kg/m') •(171 6 rr /lhour) • (1,877 hours)=257 kg of gasoline <br />' Converting kg of gasoline to pounds of gasoline yields <br /> 257 kg of gas• 2 2046 lbs of gas/kg of gas=566 7 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 566 7 lbs of gas •0 16 gal of gas/lbs of gas - 91 gallons of gasoline <br /> 1 <br /> • Advanced GeoEnvlronmental,Inc <br /> I <br /> 1 <br />