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Nitrate Mass Balance Calculation <br /> 16475 Tide Road, Ripon <br /> Data Input: <br /> Effluent Quantity(Q): 560 gals/day Concentration Rain(Nb): 1.00 mg/L-N <br /> Effluent Stream(NN,): 35.00 mg/L-N Denitrification(d): 25.0% <br /> Site Area(A): 0.94 Acres Deep Perc.of Rain(R): 2.74 in/yr <br /> Waste Loading(W): 8.01 in/yr <br /> Result: <br /> Mass Balance(Nj: 19.8 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 198% <br /> Equations: <br /> (W) in = (Q) gal x 1 W x 365 day x 1 acre x 12 in x 1 Find W <br /> yr day 7.48 gal 1 year 43,560 ftz 1 ft (A) acre <br /> 8.01 in/yr(site)=560 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/0.94 acres) <br /> N - WN 1( -d)+RNb Hantzsche-Fennemore Equation(Nc) <br /> W+R <br /> 19.81 mg/L-N=((8.01 in/yr x 35 mg/L-N x(1-0.25))+(2.74 in/yr x 1mg/L-N))/(8.01 in/yr+2.74 in/yr) <br /> Variables: <br /> Nc =Average nitrate-N concentration(mg/1)of combined effluent and rainfall percolate(19.81 mg/L-N). <br /> W= Uniform waste water loading for study area (in/yr)(8.01 inches/year). <br /> Nw =Total nitrate-N concentration of waste water percolate(35 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil(25%). <br /> R= Uniform deep percolation of rainfall(2.74 in/yr). <br /> Nb= Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1, Total nitrogen concentration of waste stream based on estimate of 35 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 2.74 in/yr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> I&-petralogix <br /> Plate 8 <br />